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  1. #1
    dj_m.o.h.t.'s Avatar
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    Es sei F(x,y)=2x+y/y-2x, x=2u-3v, y=u+2v! Man berechne dF/du und dF/dv für u=2, v=1!

  2. #2
    dj_m.o.h.t.'s Avatar
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    Meine Lösung!

    F(u,v) = 4u-6v+u+2v / u+2v-4u+6v = 5u-4v / -3u8v

    dF/du = 5*(-3u+8v)+(5u-4v)*8 / (-3u+8v)^2 = -15u+40v+15u-12v / (-3u+8v)^2 = 28v / (-3u+8v)^2

    dF/dv = -4*(-3u+8v)-(5u+4v)*8 / (-3u+8v)^2 = 12v-32u-40v+32u = -28v / (-3u+8v)^2

    dF/du (2,1) = 28 / 4 = 7

    dF/dv (2,1) = -28 / 4 = -7

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