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  1. #1
    dj_m.o.h.t.'s Avatar
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    20

    Man bestimme die Funktionalmatrix zu f:R^3->R^2:

    f(x y z) = (ln(Arctan(x+y^2) xcos(y^2-Wurzel x)*tan(xyz))

  2. #2
    dj_m.o.h.t.'s Avatar
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    Meine Lösung!

    f = ln(Arctan(x+y^2))

    g = x(cos(x-Wurzel x)tan(xyz))

    df/dx = 1 / Arctan(x+y^2) * 1 / 1 + (x+y^2)^2 * 1

    df/dy = 1 / Arctan (x+y^2) * 1 / 1 + (x+y^2)^2 * 2y

    df/dz = 0

    dg/dx = x * cos(x^2 - Wurzel x) * (1 + tan^2(xyz)) * yz

    dg/dy = x * cos(x^2 - Wurzel x) * (1 + tan^2(xyz)) * xz

    dg/dz = x * cos(x^2 - Wurzel x) * (1 + tan^2(xyz)) * xy

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