Bsp 22
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Thread: Bsp 22

  1. #1
    dj_m.o.h.t.'s Avatar
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    Bsp 22

    Es sei gu(u,v)=d/du * g(u,v) = vsin(uv) und gv(u,v)=d/dv * g(u,v) = usin(uv). Man bestimme h(t)=d/dt * g(t^2-1,3t)!

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    dj_m.o.h.t.'s Avatar
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    Meine Lösung!

    g(u,v) = -cos(u*v)

    u = t^2 - 1

    v = 3t

    g(u,v) = d/dt = -cos(3t^3 - 3t) = (9t^2 - 3) * sin(3t^3 - 3t)

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