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dj_m.o.h.t.
13-05-2002, 17:30
Es sei gu(u,v)=d/du * g(u,v) = vsin(uv) und gv(u,v)=d/dv * g(u,v) = usin(uv). Man bestimme h(t)=d/dt * g(t^2-1,3t)!

dj_m.o.h.t.
16-05-2002, 20:09
g(u,v) = -cos(u*v)

u = t^2 - 1

v = 3t

g(u,v) = d/dt = -cos(3t^3 - 3t) = (9t^2 - 3) * sin(3t^3 - 3t)